MATHS OBJ 1ecadddceee 11ccdcaaceca 21dcdeeccded 31eaadbeeadc 41bbdccdcecb 51cadbaecdec
1a) Tabulate x- 1,2,3,4 1- 1,2,3,4 2- 2_, 4, 0_ ,2_ 3- 3, 0_, 3, 0_ 4- 4_, 2_, 0_, 4 1b) I = PRT/100, p=N15000 R=10% and I=3years A = P I where I = 15000x10x3/100=N4500 A=4500 15000 =N19500 ================ 2a) using sine rule b/sin20 = 6/sin30 bsin30 = 6sin120 b 6sin120/sin30 b = 6x0.2511/0.4540 b = 5.7063/0.4540 b = 12.57 ≠ 12.6cm 2bi) the diagram is euivalent triangles. where |AX|/|BC| = |BY|/|AC| = |XY|/|YC| XY = 9, BY = 7 YC = 18-7=11 9/11 = 7/|AC| 9|AC| = 77 |AC| = 77/9 |AC| = 8cm 2bii) XY/AB = BY/AC 9/|AB| = 7/8.6 |AB| = 9x8.6/7 |AB| = 11cm ================= 3) let the son age be x man=5x son=x 4yrs ago;the man age = 5x - 4 the son age = x - 4 the product of their ages 1-4 =448 ================= 7a) 3^2n 1 - 4(3^n 1) 9=0 3^2-3 - 40 9=0 (3^n)^2-3 - 40 9=0 let 3^n = p p^2 -3 - 4-3 9=0 3p^2/3 - 12p/3 9/3 = 0 p^2 - 4p 3 = 0 p^2 - 3p - p 3 = 0 p^2p-3 - 1-3 = 0 -1-3 = 0 p-1 = 0 or p-3 = 0 p = 1 or 3 Recall 3^n = p when p=1 3^n = 3^0 n = 0 when p = 3 3^n = 3^1 n = 1 7b) log(x^2 4) = 2 logx - log^20 log(x^2 4) = log^100 = log^x - log^20 (x^2 4) = log(xx) x^2 4 = 5x x^2-5x 4 = 0 x^2-4x - x 4 = 0 x-4 - 1-4 = 0 -1-4 = 0 x-1 = 0 or x-4 = 0 x = 1 or 4
================= 4a) Convert 30000 litres to metres = 30000/1000 metres = 30metres Depth of fuel = h × 7.5×4.2 = 30m³ = 31.5hm³ = 30m³ = h = 30m³/31.5m = h = 0.9m 4b) Depth of the tank = l × b × h, where l= 7.5, b = 4.2, h = 1.2 = (7.5 × 4.2 × 1.2)m³ = 37.8m³ Convert metres to litres = 37.8 × 1000litres = 37800litres Litres of fuel needed to fill the tank=37800litres/30800litres = 7800litres 5a) Building = #48, 000 Education = #32, 000 Food = x Saving = #19, 200 Maintain = #12, 000 Miscellaneous = #7200 5b) Food = 48000 32000 19200 1200 7200 x = 144000 Food => 118400 x = 144000 Food => x = 144000 — 118400 Food = x = #25, 600 ===
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